Matematika jika [tex]{(n+3)}_C {(n+2)} =4! [/tex] nilai n adalah​

billywalkerulv – June 05, 2023

jika
[tex]{(n+3)}_C {(n+2)} =4! [/tex]
nilai n adalah​

Jawab:

kombinasi
nCr =  n!/ (n - r)! . r!

jika  (n+3) C (n +2) + 4
n = . . .

[tex]\sf \dfrac{(n+3)!}{(n+3 -(n +2))!. (n+2)!}= 4[/tex]

[tex]\sf \dfrac{(n+3)!}{1!. (n+2)!}= 4[/tex]

[tex]\sf \dfrac{(n+3)(n+2)!}{1. (n+2)!}= 4[/tex]

n + 3 = 4
n = 1

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